Optimal. Leaf size=67 \[ \frac {\left (a-b \tanh ^{-1}\left (\frac {1}{2}\right )\right ) \log \left (-\frac {1+2 c x}{2 d}\right )}{2 c}-\frac {b \text {PolyLog}(2,-1-2 c x)}{4 c}+\frac {b \text {PolyLog}\left (2,\frac {1}{3} (1+2 c x)\right )}{4 c} \]
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Rubi [A]
time = 0.05, antiderivative size = 109, normalized size of antiderivative = 1.63, number of steps
used = 4, number of rules used = 4, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {6057, 2449,
2352, 2497} \begin {gather*} -\frac {\log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 c}+\frac {\log \left (\frac {2 (2 c x+1)}{3 (c x+1)}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{2 c}+\frac {b \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{4 c}-\frac {b \text {Li}_2\left (1-\frac {2 (2 c x+1)}{3 (c x+1)}\right )}{4 c} \end {gather*}
Antiderivative was successfully verified.
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Rule 2352
Rule 2449
Rule 2497
Rule 6057
Rubi steps
\begin {align*} \int \frac {a+b \tanh ^{-1}(c x)}{1+2 c x} \, dx &=-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{2 c}+\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{2 c}+\frac {1}{2} b \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx-\frac {1}{2} b \int \frac {\log \left (\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{1-c^2 x^2} \, dx\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{2 c}+\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{2 c}-\frac {b \text {Li}_2\left (1-\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{4 c}+\frac {b \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{2 c}\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{2 c}+\frac {\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{2 c}+\frac {b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{4 c}-\frac {b \text {Li}_2\left (1-\frac {2 (1+2 c x)}{3 (1+c x)}\right )}{4 c}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.18, size = 240, normalized size = 3.58 \begin {gather*} \frac {a \log (1+2 c x)+b \tanh ^{-1}(c x) \left (\frac {1}{2} \log \left (1-c^2 x^2\right )+\log \left (i \sinh \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right )\right )\right )-\frac {1}{2} i b \left (-\frac {1}{4} i \left (\pi -2 i \tanh ^{-1}(c x)\right )^2+i \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right )^2+\left (\pi -2 i \tanh ^{-1}(c x)\right ) \log \left (1+e^{2 \tanh ^{-1}(c x)}\right )+2 i \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right ) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right )}\right )-\left (\pi -2 i \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{\sqrt {1-c^2 x^2}}\right )-2 i \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right ) \log \left (2 i \sinh \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right )\right )-i \text {PolyLog}\left (2,-e^{2 \tanh ^{-1}(c x)}\right )-i \text {PolyLog}\left (2,e^{-2 \left (\tanh ^{-1}\left (\frac {1}{2}\right )+\tanh ^{-1}(c x)\right )}\right )\right )}{2 c} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [A]
time = 0.26, size = 101, normalized size = 1.51
method | result | size |
derivativedivides | \(\frac {\frac {a \ln \left (2 c x +1\right )}{2}+\frac {b \ln \left (2 c x +1\right ) \arctanh \left (c x \right )}{2}+\frac {b \ln \left (\frac {2}{3}-\frac {2 c x}{3}\right ) \ln \left (2 c x +1\right )}{4}-\frac {b \ln \left (\frac {2}{3}-\frac {2 c x}{3}\right ) \ln \left (\frac {2 c x}{3}+\frac {1}{3}\right )}{4}-\frac {b \dilog \left (\frac {2 c x}{3}+\frac {1}{3}\right )}{4}-\frac {b \dilog \left (2 c x +2\right )}{4}-\frac {b \ln \left (2 c x +1\right ) \ln \left (2 c x +2\right )}{4}}{c}\) | \(101\) |
default | \(\frac {\frac {a \ln \left (2 c x +1\right )}{2}+\frac {b \ln \left (2 c x +1\right ) \arctanh \left (c x \right )}{2}+\frac {b \ln \left (\frac {2}{3}-\frac {2 c x}{3}\right ) \ln \left (2 c x +1\right )}{4}-\frac {b \ln \left (\frac {2}{3}-\frac {2 c x}{3}\right ) \ln \left (\frac {2 c x}{3}+\frac {1}{3}\right )}{4}-\frac {b \dilog \left (\frac {2 c x}{3}+\frac {1}{3}\right )}{4}-\frac {b \dilog \left (2 c x +2\right )}{4}-\frac {b \ln \left (2 c x +1\right ) \ln \left (2 c x +2\right )}{4}}{c}\) | \(101\) |
risch | \(\frac {b \ln \left (\frac {2 c x}{3}+\frac {1}{3}\right ) \ln \left (\frac {2}{3}-\frac {2 c x}{3}\right )}{4 c}-\frac {b \ln \left (\frac {2 c x}{3}+\frac {1}{3}\right ) \ln \left (-c x +1\right )}{4 c}+\frac {b \dilog \left (\frac {2}{3}-\frac {2 c x}{3}\right )}{4 c}+\frac {a \ln \left (-2 c x -1\right )}{2 c}-\frac {b \ln \left (-2 c x -1\right ) \ln \left (2 c x +2\right )}{4 c}+\frac {b \ln \left (-2 c x -1\right ) \ln \left (c x +1\right )}{4 c}-\frac {b \dilog \left (2 c x +2\right )}{4 c}\) | \(120\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a + b \operatorname {atanh}{\left (c x \right )}}{2 c x + 1}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {a+b\,\mathrm {atanh}\left (c\,x\right )}{2\,c\,x+1} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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